It is known that the symmetry axis of parabola is a straight line x = 1, and through (1,2) and (- 2,5), the relation of quadratic function is obtained

It is known that the symmetry axis of parabola is a straight line x = 1, and through (1,2) and (- 2,5), the relation of quadratic function is obtained

Let the analytic expression of quadratic function be y = AX2 + BX + C (a ≠ 0). Then according to the meaning of the problem, we get a + B + C = 24a − 2B + C = 5 − B2A = 1, and the solution is a = 13b = − 23C = 73, ∪ the analytic expression of the quadratic function is y = 13x2-23x + 73
Complete set u = {1,2,3,4,5,6,7,8}, known cuaucub = {1,2,3,5,7,8}, CUA ∩ B = {3,7}, Cub ∩ a = {2,8}, find a, B
You need to draw a picture and fill in the numbers
123578 is not in a or B, that is, they cannot be in a and B, so 46 is in a and B
37 is not in a, but in B,
28 is not in B but in a,
Only 15 are left outside ab
Are you satisfied with the above answers?
It is known that the symmetric axis of the parabola is a straight line x = 2, and it passes through (3,1) and (0, - 5) two points to find the analytic expression of the quadratic function
Let y = ax ^ 2 + BX + C
-B / 2A = 2
y=-2x^2+8x-5
Let the complete set u = 2.3.5.7.11.13.17.19. A intersection cub = 3.5, CUA intersection B = 7,19, CUA intersection cub = 2,17
A=3,5,11,13,
B=7,11,13,19
It is known that the axis of symmetry of the parabola is a straight line x = 1, and through (1,2) and (- 2,5), the relationship of the quadratic function is obtained=
It is known that the symmetry axis of parabola is a straight line x = 1, and through (1,2) and (- 2,5), the relation of quadratic function is obtained
What does a straight line x = 1 mean?
B of minus 2A = 1
Is it - B / 2A = 1?
Let a and B be subsets of the complete set u = {1,2,3,4}. Given (∁ UA) ∩ UB) = {2}, (∁ UA) ∩ B = {1}, then a=______ .
Because sets a and B are subsets of the complete set u = {1,2,3,4}, we know that (CUA) ∩ (cub) = {2}, (CUA) ∩ B = {1}, from the Wayne graph we know that a = {3,4}. So the answer is: {3,4}
Find the area of the quadrilateral formed by the vertex of the image and its intersection with the coordinate axis of the function y = x2-4x + 3
Let x = 0, y = 3
Let y = 0, so x ^ 2-4x + 3 = 0, x = 1 or x = 3
When x = 2, take the vertex y = - 1
So area = 1 / 2 × 3 × (3-1) + 1 / 2 × 1 × (3-1) = 4
If a set a = {y | y = 3, X ∈ r}, B = {y | y = 1-x square, X ∈ r}, then a ∩ B=
Only one 0 can be seen. What's the other one
Hello, get the range of the two functions of the constraint condition
A={y|y>0}
B={y|y≤1}
A ∩ B = {y | 00, and Y is known from b set
Given that the image of a linear function passes through a (1,6) and is parallel to the straight line y = - 2x. (1) find the expression of the linear function
Let the line be y = - 2x + B;
A (1,6) is introduced
-2+b=6；
b=8；
So the straight line is y = - 2x + 8;
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Let a = {(x, y) y (x * / 4) + (y * / 16) = 1} and B = {(x, y) y = 3 to the X}. What is the number of subsets of intersection B of a?
A is an ellipse and B is an exponential function
Draw an image
There are two intersections
So the intersection is two elements
So there are 2 & # 178; = 4 subsets