A symmetry center of image with function y = 2tan (3x + π / 4) A （π/2,0） B（7π/12,0） C （π/6,0） D （π,0）

A symmetry center of image with function y = 2tan (3x + π / 4) A （π/2,0） B（7π/12,0） C （π/6,0） D （π,0）

B hi me
If a * b = {x | x ∈ a, or X ∈ B, and X does not belong to a ∩ B}, then (a * b) * a is equal to
A * b = {x ∈ a or X ∈ B, and X does not belong to a ∩ B},
Then a * B is the part of AB that does not overlap,
So (a * b) * a coincides with a in the two regions where there is no overlap,
Then remove the overlap
So B is left
(a * b) * a = {x ∈ (a * b) or X ∈ a, and X does not belong to (a * b) ∩ a},
=If {x ∈ a ∪ B, and X does not belong to (a divided by a ∩ b)},
=B
If a * b = {x ∈ a or X ∈ B, and X does not belong to a ∩ B}, then a * B is the part that does not coincide in the two regions of AB, so (a * b) * a coincides with a with the part that does not coincide in the two regions, and then removes the part that coincides
The coordinates of the intersection of the image of the function y = 23x + 4 and the X axis are______ The coordinates of the intersection point with the y-axis are______ .
When y = 0, x = - 6; when x = 0, y = 4, the coordinates of the intersection of the image of function y = 23x + 4 and X axis are (- 6,0) and (0,4)
Let a and B be two nonempty sets, and define the difference set of a and B as A-B = {x | x ∈ a, and X ∉ B}, then a - (a-b) is equal to ()
A. AB. BC. A∩BD. A∪B
∩ A and B are two nonempty sets, A-B = {x | x ∈ a, and X ∉ B}, ∩ A-B represents the part of a that removes a ∩ B, ∩ a - (a-b) = a ∩ B
The answer is m ∩ n. the left and right circles in the figure below represent the set M, and the left, middle and right regions of N are represented by a, B, and C. Because M-N is in M, but not in N, that is, the part of m that belongs to n is removed, so M-N = am - (m-n) = M-A = b = m ∩ n
The coordinate of the intersection point of the image and the Y-axis of the linear function y = - 3x-2 is
Let x = 0 find y = - 2, so the coordinates are (0, - 2)
If M = {1,3,5,7,9}, n = {2,3,5,}, then M-N = {X / X belongs to m and X does not belong to n}=_____ .
In general, when m, n satisfy_____ CMN: the complement of N on the complete set M
If M = {1,3,5,7,9}, n = {2,3,5,}, then M-N = ({1,7,9})
In general, when m and N satisfy (n is a subset of M), M-N = CMN
Given that the image of a function y = KX + B intersects the image of another function y = 3x + 2 at a point a on the y-axis, and a point B (3, n) below the x-axis is on the image of a function y = KX + B, and N satisfies - n = 2 under the root sign, the expression of this function can be obtained
Intersect on the Y axis, x = 0, bring in y = 3x + 2, we can know a (0,2), a bring in y = KX + B, B = 2, y = KX + 2
And because n satisfies - n = 2, n = - 4, B (3, - 4) under the root sign, substituting k = - 2
y=-2x+2
y=-2x+2
If y = 3x + 2 and Y axis intersect at a (0,2), - n = 2, then n = - 2, so B (3, - 2) passes through these two points. We can get y = - 4 / 3x + 2 by simultaneous equations
Given the nonempty set M, N, define M-N = {x ｜ x ∈ m, X does not belong to n}, then M - (m-n) =?
Because M-N = {x ｜ x ∈ m, X does not belong to n},
M - (m-n) = {x ｜ x ∈ m, X does not belong to M-N},
That is, M - (m-n) = the intersection of M and n
=N and M intersection, you can try to draw V-N diagram to see
Using the University method, M-N can be seen as the intersection of M and non-n, then M - (m-n) can be seen as the intersection of non (the intersection of M and non-n) and m, that is, the intersection of (the union of non-M and N) and m, and then it comes out. The answer is the intersection of M and n
It is known that the image of a linear function y = KX + 3 passes through the point (- 2,1) and intersects with the x-axis at point B, and the image of y = 3x + B passes through the point (2,3) and intersects with the x-axis at point C,
Then, their images intersect at point a, and find the area of △ ABC
Y = KX + 3 passing point (- 2,1)
1=-2k+3
K=1
y=x+3
y=0,x=-3
So B (- 3,0)
Y = 3x + B passing through point (2,3)
3=6+b
b=-3
y=3x-3
y=0,x=1
So C (1,0)
So ABC base of triangle = | - 3-1 | = 4
y=x+3=3x-3
x=3,y=x+3=6
So a (3,6)
The height of a triangle is the distance from a to BC, that is, the x-axis
So it's the absolute value of the ordinate of A
So high = 6
So ABC area = 4 × 6 △ 2 = 12
If the image of y = KX + 3 passes through the point (- 2,1), then k = 1, y = x + 3, B (- 3,0);
If y = 3x + B passes through point (2,3), then B = - 3, y = 3x-3, C (1,0)
A (3,6) is obtained by solving the simultaneous equations of two functions
Area of △ ABC = [1 - (- 3)] * 6 / 2 = 12
Explanation: from the meaning of the title
1=-2k+3
K=1
∴y=x+3
∵ intersects the X axis
∴y=0
The solution is x = - 3
That is (- 3,0)
For set M, N, define M-N = {x | x belongs to m and X does not belong to n}, define m * n = (m-n) ∪ (n-m), let m = {y | y = x ^ 2-4x, X belongs to R},
If n = {y | y = - 2x ^ 2, X belongs to R}, then what is m * n
M = {y | y ≥ - 4} n = {y | y ≤ 0} M-N = (0, positive infinity) N-M = (negative infinity, - 4)
M * n = (negative infinity, - 4) ∪ (0, positive infinity)
^What does it mean? Question: Square