One angle of a triangle is 30 ° and the ratio of the degrees of the other two angles is 3:2. The degrees of the two angles are () and () respectively（ ）This triangle is a () triangle

One angle of a triangle is 30 ° and the ratio of the degrees of the other two angles is 3:2. The degrees of the two angles are () and () respectively（ ）This triangle is a () triangle

One angle of a triangle is 30 degrees, and the ratio of the degrees of the other two angles is 3:2. The degrees of the two angles are (90 degrees) and (60 degrees) respectively. This triangle is (right angle) triangle
The larger angle is (180-30) × 3 / (2 + 3) = 150 × 3 / 5 = 90 degree
The other angle is 180-30-90 = 60 degrees
This triangle is a right triangle
90 ° 60 ° right angle
A triangle, know the degree of an angle, know the length of both sides of this angle, how to find the degree of other angles
The length of the third side can be obtained by cosine theorem, and then the degree of other angles can be obtained by sine theorem
Cosine formula for opposite side, sine formula for angle
Finding monotone interval of function y = (tt / 2 * x + tt / 3)
Solving inequality: x ^ 2 + 2x-3 / - x ^ 2 + X + 6
The first factor is divided into x ^ 2 + 2x-3 = (x-1) (x + 3); - x ^ 2 + X + 6 = - (x-3) (x + 2)
So the original inequality can be changed to: (x-1) (x + 3) / [- (x-3) (x + 2)] 0
Equivalent to: (x-1) (x + 3) (x-3) (x + 2) > 0
Using the method of number axis root, we can get: x > 3 or - 2
x^2+2x-3/-x^2+x+60
Solve the roots of the upper and lower equations, mark them on the number axis, and draw up and down shuttle curves
You can get: X
If f (x) = sin (3x + π - 4) is shifted to the left, M is a even function and M is found
After moving left, the function is
f(x)=sin(3(x+m)+π/4)=sin(3x+3m+π/4)
Let 3x + 3M + π / 4 = π / 2 + K π, K be an integer
Then the axis of symmetry is: x = π / 12-m + K π / 3
Because f (x) is an even function, one of the symmetry axes is Y axis, that is, x = 0
So m = π / 12 + K π / 3
Solving inequality 0.2x-0.3/0.2 - x + 1 / 6
(2X-3)/2-(X+1)/6
(2x-3)/2-(x+1)/6
Given that the function f (x) = sin (x + θ) + 3cos (x − θ) is an even function, the value of θ is obtained
If f (x) is even function, then f (x) - f (- x) = 0 & nbsp; (that is, constant equal to 0) {sin (x + θ) + 3cos (x - θ) + sin (x - θ) - 3cos (x + θ) = 0 {sin (x + θ - π 3) + sin (x - θ + π 3) = 0 {2sinxcos (θ - π 3) = 0 {cos (θ - π 3) = 0} θ = k π + π 2 + π 3 (K ∈ z) and because of θ∈ (0, π), k = 0, so θ = π 2 + π 3 = 5 π 6
The solution set of inequality 2x-13x + 1 > 1 is___ .
Inequality 2x-13x + 1 ＞ 1, transfer term to get: 2x-13x + 1-1 ＞ 0, that is, x + 23x + 1 ＜ 0, can be changed into: x + 2 ＞ 03x + 1 ＜ 0 or x + 2 ＜ 03x + 1 ＞ 0, the solution is: - 2 ＜ x ＜ - 13 or no solution, then the solution set of the original inequality is {x | - 2 ＜ x ＜ - 13}
Given that the function f (x) = sin (x + θ) + 3cos (x − θ) is an even function, the value of θ is obtained
If f (x) is even function, then f (x) - f (- x) = 0 & nbsp; (i.e. constant equal to 0) {sin (x + θ) + 3cos (x - θ) + sin (x - θ) - 3cos (x + θ) = 0 {sin (x + θ - π 3) + sin (x - θ + π 3) = 0 {2sinxcos (θ - π 3) = 0 {cos (θ - π 3) = 0} θ = k π + π 2 + π 3 (k
Solving inequality (online, etc., velocity ~ ~) 1.2x-1 of 3 ≤ 3x-4 of 6
Double six on both sides
4x-2≤3x-4
4x-3x≤2-4
x≤-2
2x-1 in 3 ≤ 3x-4 in 6
2x/3-3x/6≤1-4
x/6≤-3
x≤-3*6
x≤-18