In a triangle, the sum of the degrees of two angles is equal to twice the degree of the third angle. What is the triangle?

In a triangle, the sum of the degrees of two angles is equal to twice the degree of the third angle. What is the triangle?

Equilateral triangle
The third angle is x degrees
Then 2x + x = 180
x=60
It's a triangle with an angle of 60 degrees
In a triangle, the sum of the degrees of two angles is equal to 90 degrees, which is a () triangle;
If the sum of the degrees of two angles is less than 90 degrees, this is a? Triangle
In a triangle, the sum of the degrees of two angles is equal to 90 degrees, which is a (right angle) triangle;
If the sum of the degrees of two angles is less than 90 degrees, it is an obtuse triangle
Obtuse triangle
Right triangle, obtuse triangle
In a triangle, the sum of the degrees of two angles is equal to 90 degrees, which is a (right angle) triangle;
If the sum of the degrees of two angles is less than 90 degrees, it is an obtuse triangle
Analysis: to do these two questions, you must know the knowledge points: 1. The sum of the three internal angles of a triangle is 180 degrees; 2. A triangle with one angle being a right angle is a right angle triangle, and a triangle with one angle being an obtuse angle is an obtuse angle triangle.
In a triangle, the sum of the degrees of two angles is equal to 90 degrees, which is a (right angle) triangle;
(180-90 = 90, the other angle is 90 degrees)
If there are two degrees of angles... Unfold
Analysis: to do these two questions, you must know the knowledge points: 1. The sum of the three internal angles of a triangle is 180 degrees; 2. A triangle with one angle being a right angle is a right angle triangle, and a triangle with one angle being an obtuse angle is an obtuse angle triangle.
In a triangle, the sum of the degrees of two angles is equal to 90 degrees, which is a (right angle) triangle;
(180-90 = 90, the other angle is 90 degrees)
If the sum of the degrees of two angles is less than 90 degrees, this is a (obtuse angle) triangle.
(the sum of the degrees of the two angles is less than 90 degrees, and the other angle is more than 90 degrees, which is an obtuse angle.) Put it away
Find the function y = 1-1 / 2cos π / 3x, X belongs to the minimum positive period of R
T=2π/w=2π/(π/3)=6
Set a is y = x ^ 2 + 1, B is y = x + 1, and the intersection of a and B is?
{1,0}
Finding the period of function y = - sin (3x - Π 4)
2π/3
Because the period of sin (NX) is 2 π / n
The key is to see what is the coefficient of X after it is converted into standard form!
Given a = {y | y = INX, x > 1}, B {y | y = (1 / 2) x power, x > 1}, then the intersection of ab
A = (0, positive infinity), B = (0,1 / 2), so the intersection is an open interval from 0 to 1 / 2
As soon as you draw a picture, it comes out
The minimum positive period of function y = sin (π / 3x - π / 4)
The formula of minimum positive period is: T = | 2 π / ω| (ω refers to the coefficient of x)
The minimum positive period of the function y = sin (π / 3x - π / 4) is 2 π / (π / 3) = 6
Set a = {y | y = x + 1, X_ R} , B {y | y = 2 to the power of X, X_ R} Then the intersection of a and B is
The answer is (0, positive infinity)
Both a and B sets represent the range of functions
A=R,B={y|>0}
The intersection of a and B is {y | > 0}
It is known from the title that a is the set of all real numbers, and B is the set of real numbers taken from zero, so the intersection of a and B is the set of real numbers taken from zero, that is, (0, positive infinity)
Because X in set a belongs to R, so y is equal to x + 1, which also belongs to R. because no matter what number x takes in set B, y is greater than o, so the intersection of a and B is (O, positive infinity)
The minimum positive period of function y = sin (3x - π / 2)
Let 3x - π / 2 be t, then the positive period of Sint is 2pi
So 3x - π / 2 = 2 π
X = 5 π / 6 is the minimum positive period of a function
T = 2 π / 3 is the number 3 before X
If a = {x | x * - 2x-8 ＜ 0}, B = {x | x-m ＜ 0}, if M = 3, u = Union of a and B, try to find the intersection of a and B complement
According to the meaning of the question, can we say that because x * - 2x-8 ＜ 0, (x-4) (x + 2) ＜ 0, so ① x-4 ＞ 0, x + 2 ＜ 0 solution is 4 ＜ x ＜ - 2 (rounding off); ② x-4 ＜ 0, x + 2 ＞ 0 solution is - 2 ＜ x ＜ 4, so a = {x | - 2 ＜ x ＜ 4}? Can we do this If not, please tell me why not and how to write (process)?
Strictly speaking, this way of writing is not standard (if you want to write like this, you can't make mistakes), it's better to draw a hyperbola y = x * - 2x-8, you write like this - from the image, we can see that if y