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∵函數y=log12(x2−4x−5),∴x2-4x-5>0,解得x>5,或x<-1.∵t=x2-4x-5是開口向上,對稱軸為x=2的抛物線,∴結合複合函數的性質,知函數y=log12(x2−4x−5)的遞減區間為(5,+∞).故答案為:(5,+∞).
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