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設(a,b)是原直線一點,平移後為(a+2,b+1)=(x,y), 此時a+2=x a=x-2(1) b+1=y b=y-1(2) 將(a,b)代入直線方程y=-2x b=-2a 將(1)(2)代入上式y-1=-2(x-2) y=-2x+5 即為所求
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