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A(1,0)B(4,3) C(2,4)D(0,2), AB=(3,3) CD=(-2,-2) 所以AB平行於CD AD=(-1,2) BC=(-2,1) 兩者不平行四邊形ABCD是梯形 又|AD|=|BC| 所以 所以四邊形ABCD是等腰梯形
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