Given four points a (1,0) B (4,3) C (2,4) d (0,2) on the rectangular coordinate plane, this paper proves that the quadrilateral ABCD is isosceles trapezoid

A(1,0)B(4,3)
C(2,4)D(0,2),
AB=(3,3)
CD=(-2,-2)
So AB is parallel to CD
AD=(-1,2)
BC=(-2,1)
They are not parallelogram ABCD is trapezoid
Again, ad | = | BC|
therefore
So the quadrilateral ABCD is isosceles trapezoid

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