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設x1,x2,x3的平均數為a1則:a1=1/3(x1+x2+x3)S²;=1/3[(x1-a1)²;+(x2-a1)²;+(x3-a1)²;]=5²;=25數據2x1+3,2x2+3,2x3+3的平均數為a2 a2=1/3(2x1+3+2x2+3+2x3+3)=2a1+3方差=1/3[(2x1+3-a2)²;+(2…
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