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由題目知道a+b=0.cd=1 那麼abcd=0,(a+b)cd=0 當x為正數時,有x=-2x,方程衝突,所以捨棄 當x為負數時,-x=-2x,方程衝突,所以捨棄 所以x=0 所以x²;+abcd+(a+b)cd=0
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