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設原來的兩位數為10a+b,根據題意得:10a+b+9=10b+1,解得:b=a+1,因為可取1到8個數,所以這兩位數共有8個,它們分別,12,23,34,45,56,67,78,89,它們都是個位數位比十比特數位大1的兩位數.
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