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∵sinα=4/5,α是第二象限角∴cosα=-√(1-sin²;α)=-3/5∴tanα=sinα/cosα=(4/5)/(-3/5)=-4/3又tan(α+β)=1故tanβ=tan[(α+β)-α]=[tan(α+β)-tanα]/[1+tan(α+β)*tanα](應用正切差角公式)=[1-(-4 /3)…
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