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x²;+y²;+1-(xy+x) =x²;+y²;+1-xy-x =1/2(2x²;+2y²;+2-2xy-2x) =1/2(x²;-2xy+y²;+x²;-2x+1+y²;) =1/2[(x-y)²;+(x-1)²;+y²;]>=0 ∴x²;+y²;+1>=(xy+x)
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