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因x2-(a+5)x+5a-1=(x+b)(x+c)= x2+(b+c)x+bc 故有b+c=-a-5,bc=5a-1 消去a,變形得(b+5)(c+5)=-1 因b,c是整數,故有b=-4,c=-6或b=-6,c=-4. 於是a=5
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