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由|xy |+|x+y|=1,知 0≤|xy|≤1 故有 0≤|x|·|y|≤1 而由x、y都為整數 所以,x、y兩數只能在±1、0三個數中取值 當x=0時,有y=±1 當x=1時,有y=0 當x=-1時,有y=0 所以,該方程有4組解
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