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(2013)^2013=(287*7+4)^2013用二次項展開式(287*7)^2013+.+4^2013反正就只有一項不含有287*7,即最後一項4^2013當天數是7的倍數,仍然是星期三,只看4^2013除以7的餘數是多少即可.4^1 mod 7 = 4(意思是4 ^1處以7的餘數為…
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