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先找出3的多少次方减1是7的倍數 得到3^6-1=729-1=7*104 那麼3^1998-1=729^333-1=(729-1)(729^332+729^331+.+1)=7*104*. 為7的倍數 也就是3的1998次方為7的倍數多1 3的1998次方天后是週三
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