解方程(2x-1)^2-10(2x-1)+25=0(1+√2)x^2-(1-√2)x=0用分解因式做啊

解方程(2x-1)^2-10(2x-1)+25=0(1+√2)x^2-(1-√2)x=0用分解因式做啊

(2x-1)^2-10(2x-1)+25=0(2x-1-5)²;=0(2x-6)²;=0∴x=3(1+√2)x^2-(1-√2)x=0 x[(1+√2)x-(1-√2)]=0x=0(1+√2)x-(1-√2)=0x=0 x=(1-√2)/(1+√2)=(1-√2)²;/(1-2)=-(1-√2)²;=-1+2√2-2=2√2-3∴…