To solve the equation (2x-1) ^ 2-10 (2x-1) + 25 = 0 (1 + √ 2) x ^ 2 - (1 - √ 2) x = 0, do it by factorization

To solve the equation (2x-1) ^ 2-10 (2x-1) + 25 = 0 (1 + √ 2) x ^ 2 - (1 - √ 2) x = 0, do it by factorization

(2x-1)^2-10(2x-1)+25=0 (2x-1-5)²=0(2x-6)²=0∴x=3(1+√2)x^2-(1-√2)x=0 x[(1+√2)x-(1-√2)]=0x=0 (1+√2)x-(1-√2)=0x=0 x=(1-√2)/(1+√2)=(1-√2)²/(1-2)=-(1-√2)²=-1+2√2-2=2√2-3∴...