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実数集合上の関数(x)を定義すると、f(x)がf(x)にf(y)を加えられる。 証明:x=0、y=0、f(0)=f(0)+f(0) だからf(0)=0 任意の実数xに対して、条件f(0)=f(x-x)=f(x)+f(-x) f(-x)=-f(x) f(x)は奇関数
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