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ax+y+2=0①x+ay−a+3=0②∵x,y的值互為相反數,∴x+y=0,①+②可得(a+1)x+(a+1)y+5-a=0,即(a+1)(x+y)+5-a=0③,把x+y=0代入③得5-a=0,解得a=5.故答案為:5.
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