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f(x)=1/(x-3)(x+2)=(1/5){[1/(x-3)]-[1/(x+2)]}=(1/5){[(-1/3)/(1-x/3)]-[(1/2)/(1+x/2)]} =(1/5){(-1/3)∑(x/3)^n-(1/2)∑(-x/2)^n}=-1/15∑[(1/3)^n-(-1/2)^n]x^n (-2
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