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用裂項相消求和法做… 選取1/2得到 原式=1/2(1/1-1/2)+1/2(1/2-1/3).+1/2(1/(n)-1/(n+1)) 選取1/2,合併同類項,得到1/2(1-1/(n+1))=2005/2006 然後解一下應該就OK了把…
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