lim┬（n→∞）⁡；〖（1/（n^2+1）〗+2/（n^2+2）+⋯；n/（n^2+n））等於1/2，

lim┬（n→∞）⁡；〖（1/（n^2+1）〗+2/（n^2+2）+⋯；n/（n^2+n））等於1/2，

1/（n^2+1）+n/[n^2+n]=[（n^2+n）+n（n^2+1）]/[（n^2+1）（n^2+n）]=n^3/n^4*[1+1/n+2/n^2+1/n^3]/[（1+1/n^2）（1+1/n）]2/（n^2+2）+（n-1）/[n^2+n-1]=[2（n^2+n-1）+（n-1）（n^2+2）]/[（n^2+2）（n^2+n-1）]=n^3/n^4*[1+1/n+4/n^2+-4/n^ 3…

Elden Ring Premiere

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