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五個連續的自然數中,前3個數的和正好等於後兩個數的和,這5個連續自然數的中間一個數是(6) 設中間的一個為x,則另四個數為x-2,x-1,x+1,x+2 (x-2)+(x-1)+x=(x+2)+(x+1) 3x-3=2x+3 x=6 中間的一個數為6
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