若（2x2-x-1）3=a0x6+a1x5+a2x4+a3x3+a4x2+a5x+a6，則a1+a3+a5=______.

若（2x2-x-1）3=a0x6+a1x5+a2x4+a3x3+a4x2+a5x+a6，則a1+a3+a5=______.

∵（2x2-x-1）3=a0x6+a1x5+a2x4+a3x3+a4x2+a5x+a6，令x=1得，（2-1-1）3=a0+a1+a2+a3+a4+a5+a6，∴a0+a1+a2+a3+a4+a5+a6=0…①，令x=-1得，（2+1-1）3=a0-a1+a2-a3+a4-a5+a6…②，①-②得2（a1+a3+a5）=-8，∴a1+a3+a5=-4故答案為-4.

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