((x+1)(x+2)-2)除以x化簡
((x+1)(x+2)-2)/x
=(x^2+3x+2-2)/x
=(x^2+3x)/x
=x+3
化簡(y-x/1)除以(x-y/1)的結果是
(y-1/x)/(x-1/y)=[(xy-1)/x]/[(xy-1)/y]=[(xy-1)/x]*[y/(xy-1)]=y/x
化簡(x-1-8除以x+1)除以x-3除以x+1
(x-1-8除以x+1)除以x-3除以x+1 ={(X-1)(X+1)-8}/x+1除以x-3除以x+1 =(X^2-1-8)/x-3 =(X+3)(X-3)/X-3 =X+3