已知:a+b=3,x-y=1,求a2+2ab+b2-x+y的值.

已知:a+b=3,x-y=1,求a2+2ab+b2-x+y的值.


∵a+b=3,x-y=1,∴a2+2ab+b2-x+y=(a+b)2-(x-y)=9-1=8.