The triangle ABC is an equilateral triangle, CE ⊥ plane ABC, BD ∥ CE, and CE = CA = 2bd, M is the midpoint of EA

The triangle ABC is an equilateral triangle, CE ⊥ plane ABC, BD ∥ CE, and CE = CA = 2bd, M is the midpoint of EA

Sorry, the mobile phone can't draw a picture. You can draw a sketch by yourself. BD ∥ CE makes the vertical line of CE through D. if the vertical foot is m, then DM is parallel and equal to BC. If the side length of an equilateral triangle is 2, that is DM is 2, EM = 1, De is root 5, it is easy to get DA as root 5