An eighth grade physics problem about pressure, urgent! Give the solution In April 2010, a fire broke out on an undersea oil exploration platform in Mexico. The leaked oil caused a dispute between oil companies and scientists on the amount of leakage. Xiao Ming thought that the oil density should be measured before estimation. He designed a device as shown in the figure, which contained oil in the cup and put a cube with a mass of 5.6 × (10 negative cubic) kg and a side length of CM, 3 / 4 of the volume is immersed in oil, and the depth of oil is 0.1M (g = 10N / kg) 1. What's the density of oil? (keep two decimal places) 2. How strong is oil to the bottom of the cup? Picture - let me describe it It's a cup with a narrow top and a wide bottom. Three quarters of the object is immersed in water OK, I'll add more

An eighth grade physics problem about pressure, urgent! Give the solution In April 2010, a fire broke out on an undersea oil exploration platform in Mexico. The leaked oil caused a dispute between oil companies and scientists on the amount of leakage. Xiao Ming thought that the oil density should be measured before estimation. He designed a device as shown in the figure, which contained oil in the cup and put a cube with a mass of 5.6 × (10 negative cubic) kg and a side length of CM, 3 / 4 of the volume is immersed in oil, and the depth of oil is 0.1M (g = 10N / kg) 1. What's the density of oil? (keep two decimal places) 2. How strong is oil to the bottom of the cup? Picture - let me describe it It's a cup with a narrow top and a wide bottom. Three quarters of the object is immersed in water OK, I'll add more

1. Block volume v = 2cm * 2cm * 2cm = 8cm & sup3; = 8 × 10 & # 710; (- 6) M & sup3;
Immersion volume V1 = 8 × 10 & # 710; (- 6) M & sup3; * 0.75 = 6 × 10 & # 710; (- 6) M & sup3;
When the mass floats, the buoyancy F of the mass is equal to the gravity g, f floating = g = ρ GV1, that is, ρ * GV1 = mg
The oil density ρ = m / V1 = 5.6 × 10 & # 710; (- 3) kg / [6 × 10 & # 710; (- 6) M & sup3;] = 933kg / M & sup3;
2. Pressure P = ρ GH = 933kg / M & sup3; * 10N / kg * 0.1M = 933pa