Can complex operation: (3 + 4I) (1 + I) be calculated by the law of multiplicative distribution 3 × 1 + 3 × I + 4I × 1 + 4I × I?

Can complex operation: (3 + 4I) (1 + I) be calculated by the law of multiplicative distribution 3 × 1 + 3 × I + 4I × 1 + 4I × I?

Yes, but don't forget that the square of I is - 1