Let (SiNx) = 2-cos2x, then f (COS π / 6) =?

Let (SiNx) = 2-cos2x, then f (COS π / 6) =?

The original formula = f [sin (0 / 2 - π / 6)]
=f(sin(π/3))
=2-cos(2*π/3)
=2-(-1/2)
=5/2

Elden Ring Premiere

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