[(2a + b) 2 + (2a + b) (b-2a) - 6B] / 2B, where a and B satisfy | a + half | + √ B-3 = 0

[(2a + b) 2 + (2a + b) (b-2a) - 6B] / 2B, where a and B satisfy | a + half | + √ B-3 = 0

a. B satisfies | a + half | + √ (B-3) = 0?
|A + half | > = 0, √ (B-3) > = 0,
To make the equation hold, | a + half | = 0, a = - 1 / 2; √ (B-3) = 0, B = 3;
[（2a+b）²+（2a+b）（b-2a）-6b]/(2b)?
=[（2a+b）²-（2a+b）（2a-b）-6b]/(2b)
=[4a²+4ab+b²-4a²+b²-6b]/(2b)
=2a+b-3
=2*(-1/2)+3-3
=-1

Elden Ring Premiere

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