Given the set a = {x | 2A ≤ x ≤ A & # 178; + 1}, B = = {x | X & # 178; - 3 (a + 1) x + 2 (3a + 1) ≤ 0} a ∈ R, if B contains the range of a for a?

Given the set a = {x | 2A ≤ x ≤ A & # 178; + 1}, B = = {x | X & # 178; - 3 (a + 1) x + 2 (3a + 1) ≤ 0} a ∈ R, if B contains the range of a for a?

For the set a = {x | 2A ≤ x ≤ A & # 178; + 1}, then 2A ≤ A & # 178; + 1, a ≥ 1 or a ≤ - 1 is obtained. For the set B: X & # 178; - 3 (a + 1) x + 2 (3A + 1) = [x - (3a + 1)] (x - 2) ≤ 0x1 = 3A + 1, X2 = 2. When a ≥ 1, X1 > X2, the solution set of B is 2 ≤ x ≤ 3A + 1b including a, then 2 ≤ 2a, 3A + 1 ≥ a & # 178; + 1, that is, a ≥

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