We know that the set a = {x belongs to R / ax ^ 2-3x + 2 = 0 The set a = {x belongs to R | ax ^ 2-3x + 2 = 0, a belongs to R}. 1. If a = empty set, find the value range of real number A. 2. If a is a single element set, find the value of real number a and a

We know that the set a = {x belongs to R / ax ^ 2-3x + 2 = 0 The set a = {x belongs to R | ax ^ 2-3x + 2 = 0, a belongs to R}. 1. If a = empty set, find the value range of real number A. 2. If a is a single element set, find the value of real number a and a

1. If a = empty set, then ax ^ 2-3x + 2 = 0 has no real root
Then delta = 9-8a9 / 8
The range of a is (9 / 8, + ∞)
2. If a is a single element set, then ax ^ 2-3x + 2 = 0 has two equal real roots
Then delta = 9-8a = 0, a = 9 / 8
Then a = {4 / 3}

Elden Ring Premiere

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