Let 3 ^ a = 2 denote the value of log6 (2) with a

Let 3 ^ a = 2 denote the value of log6 (2) with a

a=lg2/lg3
log6(2)=lg2/lg6
=lg2/(lg2+lg3)
=1/[(lg2+lg3)/lg2]
=1/[1+(lg3/lg2)]
=1/[1+(1/a)]
=a/(a+1)

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