Let log27 12 = a, then log6 16=

Let log27 12 = a, then log6 16=

Log (12) 27 transforms logarithm into logarithm with base 2, and omits base 2 = log27 / log12 = log (3 ^ 3) / log (3 * 2 ^ 2) = 3log3 / (2 + log3) log (12) 27 = a --- > 3log3 / (2 + log3) = a --- > log3 = 2A / (3-A) log (6) 16 = log (2 ^ 4) / log (2 * 3) = 4 / (1 + log3) = 4 / [1 + 2A / (3-A)]