Let log1227 = A and prove: log616 = 4 (3 − a) 3 + a

Let log1227 = A and prove: log616 = 4 (3 − a) 3 + a

It is proved that: ∵ log1227 = a, ∵ 4 (3 − a) 3 + a = 4 (3 − 3log123) 3 + 3log123 = 4 (1 − log123) 1 + log123 = log12124 − log1234log12 & nbsp; 36 = log12256log1236 = log36256 = log616. ∵ log616 = 4 (3 − a) 3 + a

Elden Ring Premiere

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