What is the calculation method of (2 + 1) (2 ^ 2 + 1) (2 ^ 4 + 1) (2 ^ 8 + 1) (2 ^ 16 + 1) (2 ^ 32 + 1) + 1?

What is the calculation method of (2 + 1) (2 ^ 2 + 1) (2 ^ 4 + 1) (2 ^ 8 + 1) (2 ^ 16 + 1) (2 ^ 32 + 1) + 1?

Because (2-1) = 1, we can multiply (2-1) by (2-1), and the value of the original formula remains unchanged. The original formula = (2-1) (2 + 1) (2 & # 178; + 1) (2 ^ 4 + 1) (2 ^ 8 + 1) (2 ^ 16 + 1) (2 ^ 32 + 1) + 1 = (2 & # 178; - 1) (2 & # 178; + 1) (2 ^ 4 + 1) (2 ^ 8 + 1) (2 ^ 16 + 1) (2 ^ 32 + 1) + 1 = (2 ^ 4-1) (2 ^ 4 + 1) (2 ^ 8 + 1) (2 ^ 16 + 1) (2 ^ 32 + 1) + 1