(1) If f (x) is a quadratic function, and f (0) = 1, f (x + 1) - f (x) = 2x, find (x) (2) The value range of y = radical (x2-16) is

(1) If f (x) is a quadratic function, and f (0) = 1, f (x + 1) - f (x) = 2x, find (x) (2) The value range of y = radical (x2-16) is

Let f (x) = ax ^ 2 + BX + C, from F (0) = 1 to C = 1; from F (x + 1) - f (x) = a (x + 1) ^ 2 + B (x + 1) + C - [x ^ 2 + BX + C] = 2aX + A + B = 2x, so 2A = 2, a + B = 0. From the solution, we get a = 1, B = - 1; then f (x) = x ^ 2-x + 1. (2) from x ^ 2-16 >

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