The distance between the center of a circle with x square plus y square equal to 25 and the line with x plus y plus 1 equal to 0 is

The distance between the center of a circle with x square plus y square equal to 25 and the line with x plus y plus 1 equal to 0 is

X 2; + y 2; + 6x-8y + 25 = 0 (x 2; + 6x + 9) + (y 2; - 8y + 16) = 0 (x + = - 25 / 12-2 = - 49 / 12 is transformed from the square of x plus the square of y plus 6x minus 8y plus 25 equal to 0)