Let a = [x / x2 + 4x = 0}, B = {X / x2 + 2 (a + 1) + A2-1 = 0}. (1) if a ∩ B = B, find the value of A. (2) if a ∪ B = B, find the value of A X2 is the square of X, and A2 is also the square of A

Let a = [x / x2 + 4x = 0}, B = {X / x2 + 2 (a + 1) + A2-1 = 0}. (1) if a ∩ B = B, find the value of A. (2) if a ∪ B = B, find the value of A X2 is the square of X, and A2 is also the square of A

1：A=[x/x2+4x=0}=A=[-4,0}
If B is an empty set, that is [2 (a + 1)] ^ 2-4a ^ 2 + 4

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