Given the solution x = 4 y = - 3 of the system of linear equations x + my = 4 NX + 3Y = 2, we can find the value of M + n

Given the solution x = 4 y = - 3 of the system of linear equations x + my = 4 NX + 3Y = 2, we can find the value of M + n

The solution of X + my = 4 NX + 3Y = 2 x = 4 y = - 3
4-3m=4
m=0
4n-9=2
4n=11
n=11/4
∴m+n=11/4