When Xiao Ming solved the equation 2x-1 / 5 + 1 = x + A / 2, due to carelessness, when the denominator was removed, the left 1 of the equation was not multiplied by 10, so the solution obtained was x = 4. Try to find the value of a, and correctly find the solution of the equation When Xiao Ming solved the equation 5 (2x-1) + 1 = 2 (x + a), due to carelessness, when removing the denominator, the 1 on the left side of the equation was not multiplied by 10, so the solution obtained was x = 4. Try to find the value of a and get the solution of the equation correctly.

When Xiao Ming solved the equation 2x-1 / 5 + 1 = x + A / 2, due to carelessness, when the denominator was removed, the left 1 of the equation was not multiplied by 10, so the solution obtained was x = 4. Try to find the value of a, and correctly find the solution of the equation When Xiao Ming solved the equation 5 (2x-1) + 1 = 2 (x + a), due to carelessness, when removing the denominator, the 1 on the left side of the equation was not multiplied by 10, so the solution obtained was x = 4. Try to find the value of a and get the solution of the equation correctly.

If it is not multiplied by 10, then the result of removing the denominator is: 2 * (2x-1) + 1 = 5 * (x + a) because x = 4, a = - 1 is obtained and a = - 1 is brought in
5 of (2x-1) + 1 = 2 of X + a know (2x-1) / 5 + 1 = (x-1) / 2 get: x = 13