Given that x = 5Y = 7 is the solution of the equation kx-2y-1 = 0, then K=______ .
Substituting x = 5Y = 7 into the equation kx-2y-1 = 0, we get 5k-14-1 = 0, then k = 3
Substituting x = 5Y = 7 into the equation kx-2y-1 = 0, we get 5k-14-1 = 0, then k = 3