Given that the system of equations (1) 4x + 3Y = 12, (2) X -- 3 / 2Y = 12 and equation y = kx-1 have a common solution, then K=

Given that the system of equations (1) 4x + 3Y = 12, (2) X -- 3 / 2Y = 12 and equation y = kx-1 have a common solution, then K=

4x+3y=12
x-3/2y=12 2x-3y=24
x=6 y=-4
y=kx-1
-4=6k-1
k=-1/2