(A / 1 + B / 1 + C / 1 + D / 1) + 36 / 1 + 45 / 1 = 1 a B C D is four continuous natural numbers a + B + C + D =? Urgent need

(A / 1 + B / 1 + C / 1 + D / 1) + 36 / 1 + 45 / 1 = 1 a B C D is four continuous natural numbers a + B + C + D =? Urgent need

Is the numerator and denominator in the wrong position
The least common multiple of 60 and 45 is 180
Therefore, the original formula can be changed to
1/a+1/b+1/c+1/d+5/180+4/180=1
You can get it
1/a+1/b+1/c+1/d=1-5/180-4/180=171/180
As 171 / 180 = (30 + 36 + 45 + 60) / 180 = 30 / 180 + 36 / 180 + 45 / 180 + 60 / 180 = 1 / 6 + 1 / 5 + 1 / 4 + 1 / 3
So a + B + C + D = 6 + 5 + 4 + 3 = 18
A: slightly