If X: 2 = Y: 3 = Z: 4 and X + y + Z = 18, then 2x + 3Y + 4Z=

If X: 2 = Y: 3 = Z: 4 and X + y + Z = 18, then 2x + 3Y + 4Z=

Let X: 2 = Y: 3 = Z: 4 = K
therefore
x=2k
y=3k
z=4k
therefore
2k+3k+4k=18
9k=18
k=2
therefore
x=4
y=6
z=8
So 2x + 3Y + 4Z=
=2×4+3×6+4×8
=8+18+32
=58