The variance of data x1, X2, and X10 is 2 (x1-3) square + (x2-3) square +,,, + (x10-3) square = 120 to find the average of X

The variance of data x1, X2, and X10 is 2 (x1-3) square + (x2-3) square +,,, + (x10-3) square = 120 to find the average of X

According to the meaning of the question, D (x) = e (x ^ 2) - (E (x)) ^ 2 = 2 (x1-3) ^ 2 + (x2-3) ^ 2 + (x3-3) ^ 2 + +(x10-3) ^ 2 = 120, then E {(x-3) ^ 2} = 120 / 10 = 12e (x ^ 2) = E [{(x-3) + 3} ^ 2] = E [(x-3) ^ 2 + 6 (x-3) + 9] = E [(x-3) ^ 2] + 6e [(x-3)] + 9 = 12 + 6e [x] - 6 * 3 + 9 = 3 + 6e [x], that is, D (x) = e (x ^