3, if the sum of the first n terms of the equal ratio sequence {an} is Sn = 3 ^ n + A, then a is an=sn-sn-1=2x3 n-1 ,a1=s1 ,2=3+a ,a=1 The answer is - 1 or 1,

3, if the sum of the first n terms of the equal ratio sequence {an} is Sn = 3 ^ n + A, then a is an=sn-sn-1=2x3 n-1 ,a1=s1 ,2=3+a ,a=1 The answer is - 1 or 1,

an=sn-sn-1=2x3 n-1 , a1=s1 , 2=3+a ,a=1
Your penultimate movie is right. The last step is a = - 1,
And your solution is not rigorous. An = sn-sn-1 = 2x3 n-1 if n = 2
The correct solution is A2 = 6, A1 = S1 = 3 + A, A3 = 18, so A2 * A2 = A1 * A3 get a = - 1